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Snapdrive for Unix
简体中文版经机器翻译而成，仅供参考。如与英语版出现任何冲突，应以英语版为准。

脚本示例

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以下是使用退出状态值的脚本示例。

以下脚本使用 SnapDrive for UNIX 退出状态值：

	#!/bin/sh
	# This script demonstrates a SnapDrive
	# script that uses exit codes.

	RET=0;
	#The above statement initializes RET and sets it to 0

	snapdrive snap create -dg vg22 -snapname vg22_snap1;
	# The above statement executes the snapdrive command

	RET=$?;
	#The above statement captures the return code.
	#If the operation worked, print
	#success message. If the operation failed, print
	#failure message and exit.

	if [ $RET -eq 0 ]; then
	echo "snapshot created successfully"
	else
	echo "snapshot creation failed, snapdrive exit code was $RET"
	exit 1
	fi
	exit 0;

如果 RET=0 ，则命令已成功执行，并且脚本输出以下内容：

	# ./tst_script
	snap create: snapshot vg22_snap1 contains:
	disk group vg22 containing host volumes
	lvol1
	snap create: created snapshot betty:/vol/vol2:vg22_snap1
	snapshot created successfully

如果 RET = 非零值，则命令未成功执行。以下示例显示了典型输出：

	# ./tst_script
	0001-185 Command error: snapshot betty:/vol/vol2:vg22_snap1 already
	exists on betty:/vol/vol2.
	Please use -f (force) flag to overwrite existing snapshot
	snapshot creation failed, snapdrive exit code was 4